-2(2x+3)=4(x+2)-3(2x-2)

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Solution for -2(2x+3)=4(x+2)-3(2x-2) equation: 



-2(2x+3)=4(x+2)-3(2x-2)

We move all terms to the left:

-2(2x+3)-(4(x+2)-3(2x-2))=0

We multiply parentheses

-4x-(4(x+2)-3(2x-2))-6=0



We calculate terms in parentheses: -(4(x+2)-3(2x-2)), so:

4(x+2)-3(2x-2)

We multiply parentheses

4x-6x+8+6

We add all the numbers together, and all the variables

-2x+14

Back to the equation:

-(-2x+14)



We get rid of parentheses

-4x+2x-14-6=0

We add all the numbers together, and all the variables

-2x-20=0

We move all terms containing x to the left, all other terms to the right

-2x=20

x=20/-2

x=-10

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