-2(2x-3)=3(x+1)=10

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Solution for -2(2x-3)=3(x+1)=10 equation: 



-2(2x-3)=3(x+1)=10

We move all terms to the left:

-2(2x-3)-(3(x+1))=0

We multiply parentheses

-4x-(3(x+1))+6=0



We calculate terms in parentheses: -(3(x+1)), so:

3(x+1)

We multiply parentheses

3x+3

Back to the equation:

-(3x+3)



We get rid of parentheses

-4x-3x-3+6=0

We add all the numbers together, and all the variables

-7x+3=0

We move all terms containing x to the left, all other terms to the right

-7x=-3

x=-3/-7

x=3/7

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