-2(2x-3)=3(x+1)=10

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Solution for -2(2x-3)=3(x+1)=10 equation:



-2(2x-3)=3(x+1)=10
We move all terms to the left:
-2(2x-3)-(3(x+1))=0
We multiply parentheses
-4x-(3(x+1))+6=0
We calculate terms in parentheses: -(3(x+1)), so:
3(x+1)
We multiply parentheses
3x+3
Back to the equation:
-(3x+3)
We get rid of parentheses
-4x-3x-3+6=0
We add all the numbers together, and all the variables
-7x+3=0
We move all terms containing x to the left, all other terms to the right
-7x=-3
x=-3/-7
x=3/7

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