-2(2x-4)-8=3(4x+0)-5

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Solution for -2(2x-4)-8=3(4x+0)-5 equation: 



-2(2x-4)-8=3(4x+0)-5

We move all terms to the left:

-2(2x-4)-8-(3(4x+0)-5)=0

We add all the numbers together, and all the variables

-2(2x-4)-(3(+4x)-5)-8=0

We multiply parentheses

-4x-(3(+4x)-5)+8-8=0



We calculate terms in parentheses: -(3(+4x)-5), so:

3(+4x)-5

We multiply parentheses

12x-5

Back to the equation:

-(12x-5)



We add all the numbers together, and all the variables

-4x-(12x-5)=0

We get rid of parentheses

-4x-12x+5=0

We add all the numbers together, and all the variables

-16x+5=0

We move all terms containing x to the left, all other terms to the right

-16x=-5

x=-5/-16

x=5/16

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