-2(2x/3)=-4(x/1)-2

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Solution for -2(2x/3)=-4(x/1)-2 equation:



-2(2x/3)=-4(x/1)-2
We move all terms to the left:
-2(2x/3)-(-4(x/1)-2)=0
We add all the numbers together, and all the variables
-2(+2x/3)-(-4(+x/1)-2)=0
We multiply parentheses
-4x-(-4(+x/1)-2)=0
We multiply all the terms by the denominator
-4x*1)-2)-(-4(+x=0
We add all the numbers together, and all the variables
x-4x*1)-2)-(-4(=0
Wy multiply elements
-4x^2+x=0
a = -4; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-4)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-4}=\frac{-2}{-8} =1/4 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-4}=\frac{0}{-8} =0 $

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