-2(2y+3)+2=16

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Solution for -2(2y+3)+2=16 equation: 



-2(2y+3)+2=16

We move all terms to the left:

-2(2y+3)+2-(16)=0

We add all the numbers together, and all the variables

-2(2y+3)-14=0

We multiply parentheses

-4y-6-14=0

We add all the numbers together, and all the variables

-4y-20=0

We move all terms containing y to the left, all other terms to the right

-4y=20

y=20/-4

y=-5

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