-2(2y-1)+8y=-5(y+2)

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Solution for -2(2y-1)+8y=-5(y+2) equation: 



-2(2y-1)+8y=-5(y+2)

We move all terms to the left:

-2(2y-1)+8y-(-5(y+2))=0

We add all the numbers together, and all the variables

8y-2(2y-1)-(-5(y+2))=0

We multiply parentheses

8y-4y-(-5(y+2))+2=0



We calculate terms in parentheses: -(-5(y+2)), so:

-5(y+2)

We multiply parentheses

-5y-10

Back to the equation:

-(-5y-10)



We add all the numbers together, and all the variables

4y-(-5y-10)+2=0

We get rid of parentheses

4y+5y+10+2=0

We add all the numbers together, and all the variables

9y+12=0

We move all terms containing y to the left, all other terms to the right

9y=-12

y=-12/9

y=-1+1/3

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