-2(2y-2)+9y=-3(y+2)

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Solution for -2(2y-2)+9y=-3(y+2) equation: 



-2(2y-2)+9y=-3(y+2)

We move all terms to the left:

-2(2y-2)+9y-(-3(y+2))=0

We add all the numbers together, and all the variables

9y-2(2y-2)-(-3(y+2))=0

We multiply parentheses

9y-4y-(-3(y+2))+4=0



We calculate terms in parentheses: -(-3(y+2)), so:

-3(y+2)

We multiply parentheses

-3y-6

Back to the equation:

-(-3y-6)



We add all the numbers together, and all the variables

5y-(-3y-6)+4=0

We get rid of parentheses

5y+3y+6+4=0

We add all the numbers together, and all the variables

8y+10=0

We move all terms containing y to the left, all other terms to the right

8y=-10

y=-10/8

y=-1+1/4

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