-2(2y-3)-y=-3(y-4)

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Solution for -2(2y-3)-y=-3(y-4) equation: 



-2(2y-3)-y=-3(y-4)

We move all terms to the left:

-2(2y-3)-y-(-3(y-4))=0

We add all the numbers together, and all the variables

-1y-2(2y-3)-(-3(y-4))=0

We multiply parentheses

-1y-4y-(-3(y-4))+6=0



We calculate terms in parentheses: -(-3(y-4)), so:

-3(y-4)

We multiply parentheses

-3y+12

Back to the equation:

-(-3y+12)



We add all the numbers together, and all the variables

-5y-(-3y+12)+6=0

We get rid of parentheses

-5y+3y-12+6=0

We add all the numbers together, and all the variables

-2y-6=0

We move all terms containing y to the left, all other terms to the right

-2y=6

y=6/-2

y=-3

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