-2(2y-4)+3y=7

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Solution for -2(2y-4)+3y=7 equation: 



-2(2y-4)+3y=7

We move all terms to the left:

-2(2y-4)+3y-(7)=0

We add all the numbers together, and all the variables

3y-2(2y-4)-7=0

We multiply parentheses

3y-4y+8-7=0

We add all the numbers together, and all the variables

-1y+1=0

We move all terms containing y to the left, all other terms to the right

-y=-1

y=-1/-1

y=1

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