-2(2y-4)-y=-4(y-4)

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Solution for -2(2y-4)-y=-4(y-4) equation: 



-2(2y-4)-y=-4(y-4)

We move all terms to the left:

-2(2y-4)-y-(-4(y-4))=0

We add all the numbers together, and all the variables

-1y-2(2y-4)-(-4(y-4))=0

We multiply parentheses

-1y-4y-(-4(y-4))+8=0



We calculate terms in parentheses: -(-4(y-4)), so:

-4(y-4)

We multiply parentheses

-4y+16

Back to the equation:

-(-4y+16)



We add all the numbers together, and all the variables

-5y-(-4y+16)+8=0

We get rid of parentheses

-5y+4y-16+8=0

We add all the numbers together, and all the variables

-1y-8=0

We move all terms containing y to the left, all other terms to the right

-y=8

y=8/-1

y=-8

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