-2(2y-5)+3y=8

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Solution for -2(2y-5)+3y=8 equation: 



-2(2y-5)+3y=8

We move all terms to the left:

-2(2y-5)+3y-(8)=0

We add all the numbers together, and all the variables

3y-2(2y-5)-8=0

We multiply parentheses

3y-4y+10-8=0

We add all the numbers together, and all the variables

-1y+2=0

We move all terms containing y to the left, all other terms to the right

-y=-2

y=-2/-1

y=+2

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