-2(2y-5)+3y=8

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Solution for -2(2y-5)+3y=8 equation:



-2(2y-5)+3y=8
We move all terms to the left:
-2(2y-5)+3y-(8)=0
We add all the numbers together, and all the variables
3y-2(2y-5)-8=0
We multiply parentheses
3y-4y+10-8=0
We add all the numbers together, and all the variables
-1y+2=0
We move all terms containing y to the left, all other terms to the right
-y=-2
y=-2/-1
y=+2

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