-2(2z-3)=3(z+1)+10

Solution for -2(2z-3)=3(z+1)+10 equation:

-2(2z-3)=3(z+1)+10

We move all terms to the left:

-2(2z-3)-(3(z+1)+10)=0

We multiply parentheses

-4z-(3(z+1)+10)+6=0


We calculate terms in parentheses: -(3(z+1)+10), so:

3(z+1)+10

We multiply parentheses

3z+3+10

We add all the numbers together, and all the variables

3z+13

Back to the equation:

-(3z+13)


We get rid of parentheses

-4z-3z-13+6=0

We add all the numbers together, and all the variables

-7z-7=0

We move all terms containing z to the left, all other terms to the right

-7z=7

z=7/-7

z=-1