-2(3-1)+3(j+4)=4

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Solution for -2(3-1)+3(j+4)=4 equation: 



-2(3-1)+3(j+4)=4

We move all terms to the left:

-2(3-1)+3(j+4)-(4)=0

determiningTheFunctionDomain
3(j+4)-4-2(3-1)=0

We add all the numbers together, and all the variables

3(j+4)-4-22=0

We add all the numbers together, and all the variables

3(j+4)-26=0

We multiply parentheses

3j+12-26=0

We add all the numbers together, and all the variables

3j-14=0

We move all terms containing j to the left, all other terms to the right

3j=14

j=14/3

j=4+2/3

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