-2(3-2c)=10-4c

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Solution for -2(3-2c)=10-4c equation: 



-2(3-2c)=10-4c

We move all terms to the left:

-2(3-2c)-(10-4c)=0

We add all the numbers together, and all the variables

-2(-2c+3)-(-4c+10)=0

We multiply parentheses

4c-(-4c+10)-6=0

We get rid of parentheses

4c+4c-10-6=0

We add all the numbers together, and all the variables

8c-16=0

We move all terms containing c to the left, all other terms to the right

8c=16

c=16/8

c=2

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