-2(3-2x)=-6x+8(x+2)

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Solution for -2(3-2x)=-6x+8(x+2) equation:



-2(3-2x)=-6x+8(x+2)
We move all terms to the left:
-2(3-2x)-(-6x+8(x+2))=0
We add all the numbers together, and all the variables
-2(-2x+3)-(-6x+8(x+2))=0
We multiply parentheses
4x-(-6x+8(x+2))-6=0
We calculate terms in parentheses: -(-6x+8(x+2)), so:
-6x+8(x+2)
We multiply parentheses
-6x+8x+16
We add all the numbers together, and all the variables
2x+16
Back to the equation:
-(2x+16)
We get rid of parentheses
4x-2x-16-6=0
We add all the numbers together, and all the variables
2x-22=0
We move all terms containing x to the left, all other terms to the right
2x=22
x=22/2
x=11

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