-2(3-2z)=7z+9

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Solution for -2(3-2z)=7z+9 equation: 



-2(3-2z)=7z+9

We move all terms to the left:

-2(3-2z)-(7z+9)=0

We add all the numbers together, and all the variables

-2(-2z+3)-(7z+9)=0

We multiply parentheses

4z-(7z+9)-6=0

We get rid of parentheses

4z-7z-9-6=0

We add all the numbers together, and all the variables

-3z-15=0

We move all terms containing z to the left, all other terms to the right

-3z=15

z=15/-3

z=-5

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