-2(3-z)+7z=12z-(z+4)

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Solution for -2(3-z)+7z=12z-(z+4) equation: 



-2(3-z)+7z=12z-(z+4)

We move all terms to the left:

-2(3-z)+7z-(12z-(z+4))=0

We add all the numbers together, and all the variables

-2(-1z+3)+7z-(12z-(z+4))=0

We add all the numbers together, and all the variables

7z-2(-1z+3)-(12z-(z+4))=0

We multiply parentheses

7z+2z-(12z-(z+4))-6=0



We calculate terms in parentheses: -(12z-(z+4)), so:

12z-(z+4)

We get rid of parentheses

12z-z-4

We add all the numbers together, and all the variables

11z-4

Back to the equation:

-(11z-4)



We add all the numbers together, and all the variables

9z-(11z-4)-6=0

We get rid of parentheses

9z-11z+4-6=0

We add all the numbers together, and all the variables

-2z-2=0

We move all terms containing z to the left, all other terms to the right

-2z=2

z=2/-2

z=-1

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