-2(3/2y+3)+3y=-6

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Solution for -2(3/2y+3)+3y=-6 equation:



-2(3/2y+3)+3y=-6
We move all terms to the left:
-2(3/2y+3)+3y-(-6)=0
Domain of the equation: 2y+3)!=0
y∈R
We add all the numbers together, and all the variables
3y-2(3/2y+3)+6=0
We multiply parentheses
3y-6y-6+6=0
We add all the numbers together, and all the variables
-3y=0
y=0/-3
y=0

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