-2(3/5)t=-22

Solution for -2(3/5)t=-22 equation:

-2(3/5)t=-22

We move all terms to the left:

-2(3/5)t-(-22)=0


Domain of the equation: 5)t!=0

t!=0/1

t!=0

t∈R


We add all the numbers together, and all the variables

-2(+3/5)t-(-22)=0

We add all the numbers together, and all the variables

-2(+3/5)t+22=0

We multiply parentheses

-6t^2+22=0

a = -6; b = 0; c = +22;
Δ = b2-4ac
Δ = 02-4·(-6)·22
Δ = 528
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{528}=\sqrt{16*33}=\sqrt{16}*\sqrt{33}=4\sqrt{33}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{33}}{2*-6}=\frac{0-4\sqrt{33}}{-12}
=-\frac{4\sqrt{33}}{-12}
=-\frac{\sqrt{33}}{-3}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{33}}{2*-6}=\frac{0+4\sqrt{33}}{-12}
=\frac{4\sqrt{33}}{-12}
=\frac{\sqrt{33}}{-3}
$