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-2(3-8)=2/3(3D-60)
We move all terms to the left:
-2(3-8)-(2/3(3D-60))=0
Domain of the equation: 3(3D-60))!=0We add all the numbers together, and all the variables
D∈R
-(2/3(3D-60))-2(-5)=0
We add all the numbers together, and all the variables
-(2/3(3D-60))+10=0
We multiply all the terms by the denominator
-(2+10*3(3D-60))=0
We calculate terms in parentheses: -(2+10*3(3D-60)), so:We add all the numbers together, and all the variables
2+10*3(3D-60)
determiningTheFunctionDomain 10*3(3D-60)+2
Wy multiply elements
30D(3+2
Back to the equation:
-(30D(3+2)
-(30D5=0
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