-2(3a+2)=1/3(7-3a)

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Solution for -2(3a+2)=1/3(7-3a) equation: 



-2(3a+2)=1/3(7-3a)

We move all terms to the left:

-2(3a+2)-(1/3(7-3a))=0



Domain of the equation: 3(7-3a))!=0

a∈R



We add all the numbers together, and all the variables

-2(3a+2)-(1/3(-3a+7))=0

We multiply parentheses

-6a-(1/3(-3a+7))-4=0

We multiply all the terms by the denominator


-6a*3(-3a+7))-(1-4*3(-3a+7))=0

Wy multiply elements

-18a^2(--12a(-=0

We use the square of the difference formula

-18a^2(+12a(-=0

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