-2(3a+5)=4a(4a-2)

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Solution for -2(3a+5)=4a(4a-2) equation: 



-2(3a+5)=4a(4a-2)

We move all terms to the left:

-2(3a+5)-(4a(4a-2))=0

We multiply parentheses

-6a-(4a(4a-2))-10=0



We calculate terms in parentheses: -(4a(4a-2)), so:

4a(4a-2)

We multiply parentheses

16a^2-8a

Back to the equation:

-(16a^2-8a)



We get rid of parentheses

-16a^2-6a+8a-10=0

We add all the numbers together, and all the variables

-16a^2+2a-10=0

a = -16; b = 2; c = -10;
Δ = b2-4ac
Δ = 22-4·(-16)·(-10)
Δ = -636
Delta is less than zero, so there is no solution for the equation

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