-2(3d+2)=4(1-3d)

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Solution for -2(3d+2)=4(1-3d) equation: 



-2(3d+2)=4(1-3d)

We move all terms to the left:

-2(3d+2)-(4(1-3d))=0

We add all the numbers together, and all the variables

-2(3d+2)-(4(-3d+1))=0

We multiply parentheses

-6d-(4(-3d+1))-4=0



We calculate terms in parentheses: -(4(-3d+1)), so:

4(-3d+1)

We multiply parentheses

-12d+4

Back to the equation:

-(-12d+4)



We get rid of parentheses

-6d+12d-4-4=0

We add all the numbers together, and all the variables

6d-8=0

We move all terms containing d to the left, all other terms to the right

6d=8

d=8/6

d=1+1/3

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