-2(3n-4)-8(n-2)=-n-n

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Solution for -2(3n-4)-8(n-2)=-n-n equation: 



-2(3n-4)-8(n-2)=-n-n

We move all terms to the left:

-2(3n-4)-8(n-2)-(-n-n)=0

We add all the numbers together, and all the variables

-2(3n-4)-8(n-2)-(-2n)=0

We multiply parentheses

-6n-8n-(-2n)+8+16=0

We get rid of parentheses

-6n-8n+2n+8+16=0

We add all the numbers together, and all the variables

-12n+24=0

We move all terms containing n to the left, all other terms to the right

-12n=-24

n=-24/-12

n=+2

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