-2(3n-5)+7(n+4)=7n-1-3n

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Solution for -2(3n-5)+7(n+4)=7n-1-3n equation: 



-2(3n-5)+7(n+4)=7n-1-3n

We move all terms to the left:

-2(3n-5)+7(n+4)-(7n-1-3n)=0

We add all the numbers together, and all the variables

-2(3n-5)+7(n+4)-(4n-1)=0

We multiply parentheses

-6n+7n-(4n-1)+10+28=0

We get rid of parentheses

-6n+7n-4n+1+10+28=0

We add all the numbers together, and all the variables

-3n+39=0

We move all terms containing n to the left, all other terms to the right

-3n=-39

n=-39/-3

n=+13

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