-2(3q-2)=1/3(7-3q)

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Solution for -2(3q-2)=1/3(7-3q) equation: 



-2(3q-2)=1/3(7-3q)

We move all terms to the left:

-2(3q-2)-(1/3(7-3q))=0



Domain of the equation: 3(7-3q))!=0

q∈R



We add all the numbers together, and all the variables

-2(3q-2)-(1/3(-3q+7))=0

We multiply parentheses

-6q-(1/3(-3q+7))+4=0

We multiply all the terms by the denominator


-6q*3(-3q+7))-(1+4*3(-3q+7))=0

Wy multiply elements

-18q^2(-+12q(-=0

We use the square of the difference formula

-18q^2(-12q(-=0

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