-2(3r-4)+2=16

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Solution for -2(3r-4)+2=16 equation: 



-2(3r-4)+2=16

We move all terms to the left:

-2(3r-4)+2-(16)=0

We add all the numbers together, and all the variables

-2(3r-4)-14=0

We multiply parentheses

-6r+8-14=0

We add all the numbers together, and all the variables

-6r-6=0

We move all terms containing r to the left, all other terms to the right

-6r=6

r=6/-6

r=-1

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