-2(3u-4)+4u=6(u+2)

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Solution for -2(3u-4)+4u=6(u+2) equation: 



-2(3u-4)+4u=6(u+2)

We move all terms to the left:

-2(3u-4)+4u-(6(u+2))=0

We add all the numbers together, and all the variables

4u-2(3u-4)-(6(u+2))=0

We multiply parentheses

4u-6u-(6(u+2))+8=0



We calculate terms in parentheses: -(6(u+2)), so:

6(u+2)

We multiply parentheses

6u+12

Back to the equation:

-(6u+12)



We add all the numbers together, and all the variables

-2u-(6u+12)+8=0

We get rid of parentheses

-2u-6u-12+8=0

We add all the numbers together, and all the variables

-8u-4=0

We move all terms containing u to the left, all other terms to the right

-8u=4

u=4/-8

u=-1/2

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