-2(3v-6)+4v=5+4(2v-2)

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Solution for -2(3v-6)+4v=5+4(2v-2) equation: 



-2(3v-6)+4v=5+4(2v-2)

We move all terms to the left:

-2(3v-6)+4v-(5+4(2v-2))=0

We add all the numbers together, and all the variables

4v-2(3v-6)-(5+4(2v-2))=0

We multiply parentheses

4v-6v-(5+4(2v-2))+12=0



We calculate terms in parentheses: -(5+4(2v-2)), so:

5+4(2v-2)

determiningTheFunctionDomain
4(2v-2)+5

We multiply parentheses

8v-8+5

We add all the numbers together, and all the variables

8v-3

Back to the equation:

-(8v-3)



We add all the numbers together, and all the variables

-2v-(8v-3)+12=0

We get rid of parentheses

-2v-8v+3+12=0

We add all the numbers together, and all the variables

-10v+15=0

We move all terms containing v to the left, all other terms to the right

-10v=-15

v=-15/-10

v=1+1/2

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