-2(3x+1)+3(4-x)=4(5x-2)+3x

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Solution for -2(3x+1)+3(4-x)=4(5x-2)+3x equation: 



-2(3x+1)+3(4-x)=4(5x-2)+3x

We move all terms to the left:

-2(3x+1)+3(4-x)-(4(5x-2)+3x)=0

We add all the numbers together, and all the variables

-2(3x+1)+3(-1x+4)-(4(5x-2)+3x)=0

We multiply parentheses

-6x-3x-(4(5x-2)+3x)-2+12=0



We calculate terms in parentheses: -(4(5x-2)+3x), so:

4(5x-2)+3x

We add all the numbers together, and all the variables

3x+4(5x-2)

We multiply parentheses

3x+20x-8

We add all the numbers together, and all the variables

23x-8

Back to the equation:

-(23x-8)



We add all the numbers together, and all the variables

-9x-(23x-8)+10=0

We get rid of parentheses

-9x-23x+8+10=0

We add all the numbers together, and all the variables

-32x+18=0

We move all terms containing x to the left, all other terms to the right

-32x=-18

x=-18/-32

x=9/16

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