-2(3x+7)=-3(2x+8);x=-5

Solution for -2(3x+7)=-3(2x+8);x=-5 equation:

-2(3x+7)=-3(2x+8)x=-5

We move all terms to the left:

-2(3x+7)-(-3(2x+8)x)=0

We multiply parentheses

-6x-(-3(2x+8)x)-14=0


We calculate terms in parentheses: -(-3(2x+8)x), so:

-3(2x+8)x

We multiply parentheses

-6x^2-24x

Back to the equation:

-(-6x^2-24x)


We get rid of parentheses

6x^2+24x-6x-14=0

We add all the numbers together, and all the variables

6x^2+18x-14=0

a = 6; b = 18; c = -14;
Δ = b2-4ac
Δ = 182-4·6·(-14)
Δ = 660
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{660}=\sqrt{4*165}=\sqrt{4}*\sqrt{165}=2\sqrt{165}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-2\sqrt{165}}{2*6}=\frac{-18-2\sqrt{165}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+2\sqrt{165}}{2*6}=\frac{-18+2\sqrt{165}}{12}
$