-2(3x-)=4(x+3)+8

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Solution for -2(3x-)=4(x+3)+8 equation: 



-2(3x-)=4(x+3)+8

We move all terms to the left:

-2(3x-)-(4(x+3)+8)=0

We add all the numbers together, and all the variables

-2(+3x)-(4(x+3)+8)=0

We multiply parentheses

-6x-(4(x+3)+8)=0



We calculate terms in parentheses: -(4(x+3)+8), so:

4(x+3)+8

We multiply parentheses

4x+12+8

We add all the numbers together, and all the variables

4x+20

Back to the equation:

-(4x+20)



We get rid of parentheses

-6x-4x-20=0

We add all the numbers together, and all the variables

-10x-20=0

We move all terms containing x to the left, all other terms to the right

-10x=20

x=20/-10

x=-2

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