-2(3x-2)+4x=6(x+1)

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Solution for -2(3x-2)+4x=6(x+1) equation: 



-2(3x-2)+4x=6(x+1)

We move all terms to the left:

-2(3x-2)+4x-(6(x+1))=0

We add all the numbers together, and all the variables

4x-2(3x-2)-(6(x+1))=0

We multiply parentheses

4x-6x-(6(x+1))+4=0



We calculate terms in parentheses: -(6(x+1)), so:

6(x+1)

We multiply parentheses

6x+6

Back to the equation:

-(6x+6)



We add all the numbers together, and all the variables

-2x-(6x+6)+4=0

We get rid of parentheses

-2x-6x-6+4=0

We add all the numbers together, and all the variables

-8x-2=0

We move all terms containing x to the left, all other terms to the right

-8x=2

x=2/-8

x=-1/4

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