-2(3x-2)=4(-x+4)

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Solution for -2(3x-2)=4(-x+4) equation: 



-2(3x-2)=4(-x+4)

We move all terms to the left:

-2(3x-2)-(4(-x+4))=0

We add all the numbers together, and all the variables

-2(3x-2)-(4(-1x+4))=0

We multiply parentheses

-6x-(4(-1x+4))+4=0



We calculate terms in parentheses: -(4(-1x+4)), so:

4(-1x+4)

We multiply parentheses

-4x+16

Back to the equation:

-(-4x+16)



We get rid of parentheses

-6x+4x-16+4=0

We add all the numbers together, and all the variables

-2x-12=0

We move all terms containing x to the left, all other terms to the right

-2x=12

x=12/-2

x=-6

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