-2(3x-4)+12=5(-2x+8)

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Solution for -2(3x-4)+12=5(-2x+8) equation: 



-2(3x-4)+12=5(-2x+8)

We move all terms to the left:

-2(3x-4)+12-(5(-2x+8))=0

We multiply parentheses

-6x-(5(-2x+8))+8+12=0



We calculate terms in parentheses: -(5(-2x+8)), so:

5(-2x+8)

We multiply parentheses

-10x+40

Back to the equation:

-(-10x+40)



We add all the numbers together, and all the variables

-6x-(-10x+40)+20=0

We get rid of parentheses

-6x+10x-40+20=0

We add all the numbers together, and all the variables

4x-20=0

We move all terms containing x to the left, all other terms to the right

4x=20

x=20/4

x=5

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