-2(3x-5)=-4(x-3)+8

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Solution for -2(3x-5)=-4(x-3)+8 equation: 



-2(3x-5)=-4(x-3)+8

We move all terms to the left:

-2(3x-5)-(-4(x-3)+8)=0

We multiply parentheses

-6x-(-4(x-3)+8)+10=0



We calculate terms in parentheses: -(-4(x-3)+8), so:

-4(x-3)+8

We multiply parentheses

-4x+12+8

We add all the numbers together, and all the variables

-4x+20

Back to the equation:

-(-4x+20)



We get rid of parentheses

-6x+4x-20+10=0

We add all the numbers together, and all the variables

-2x-10=0

We move all terms containing x to the left, all other terms to the right

-2x=10

x=10/-2

x=-5

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