-2(3x-5)=3(-x+2)-2

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Solution for -2(3x-5)=3(-x+2)-2 equation: 



-2(3x-5)=3(-x+2)-2

We move all terms to the left:

-2(3x-5)-(3(-x+2)-2)=0

We add all the numbers together, and all the variables

-2(3x-5)-(3(-1x+2)-2)=0

We multiply parentheses

-6x-(3(-1x+2)-2)+10=0



We calculate terms in parentheses: -(3(-1x+2)-2), so:

3(-1x+2)-2

We multiply parentheses

-3x+6-2

We add all the numbers together, and all the variables

-3x+4

Back to the equation:

-(-3x+4)



We get rid of parentheses

-6x+3x-4+10=0

We add all the numbers together, and all the variables

-3x+6=0

We move all terms containing x to the left, all other terms to the right

-3x=-6

x=-6/-3

x=+2

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