-2(3y+1)=-6y-2

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Solution for -2(3y+1)=-6y-2 equation: 



-2(3y+1)=-6y-2

We move all terms to the left:

-2(3y+1)-(-6y-2)=0

We multiply parentheses

-6y-(-6y-2)-2=0

We get rid of parentheses

-6y+6y+2-2=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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