-2(3y-1)+4y=3(1-5y)

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Solution for -2(3y-1)+4y=3(1-5y) equation: 



-2(3y-1)+4y=3(1-5y)

We move all terms to the left:

-2(3y-1)+4y-(3(1-5y))=0

We add all the numbers together, and all the variables

-2(3y-1)+4y-(3(-5y+1))=0

We add all the numbers together, and all the variables

4y-2(3y-1)-(3(-5y+1))=0

We multiply parentheses

4y-6y-(3(-5y+1))+2=0



We calculate terms in parentheses: -(3(-5y+1)), so:

3(-5y+1)

We multiply parentheses

-15y+3

Back to the equation:

-(-15y+3)



We add all the numbers together, and all the variables

-2y-(-15y+3)+2=0

We get rid of parentheses

-2y+15y-3+2=0

We add all the numbers together, and all the variables

13y-1=0

We move all terms containing y to the left, all other terms to the right

13y=1

y=1/13

y=1/13

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