-2(3y-1)+4y=6+2(4y-1)

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Solution for -2(3y-1)+4y=6+2(4y-1) equation: 



-2(3y-1)+4y=6+2(4y-1)

We move all terms to the left:

-2(3y-1)+4y-(6+2(4y-1))=0

We add all the numbers together, and all the variables

4y-2(3y-1)-(6+2(4y-1))=0

We multiply parentheses

4y-6y-(6+2(4y-1))+2=0



We calculate terms in parentheses: -(6+2(4y-1)), so:

6+2(4y-1)

determiningTheFunctionDomain
2(4y-1)+6

We multiply parentheses

8y-2+6

We add all the numbers together, and all the variables

8y+4

Back to the equation:

-(8y+4)



We add all the numbers together, and all the variables

-2y-(8y+4)+2=0

We get rid of parentheses

-2y-8y-4+2=0

We add all the numbers together, and all the variables

-10y-2=0

We move all terms containing y to the left, all other terms to the right

-10y=2

y=2/-10

y=-1/5

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