-2(3y-3)+2y=8+2(6y-2)

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Solution for -2(3y-3)+2y=8+2(6y-2) equation: 



-2(3y-3)+2y=8+2(6y-2)

We move all terms to the left:

-2(3y-3)+2y-(8+2(6y-2))=0

We add all the numbers together, and all the variables

2y-2(3y-3)-(8+2(6y-2))=0

We multiply parentheses

2y-6y-(8+2(6y-2))+6=0



We calculate terms in parentheses: -(8+2(6y-2)), so:

8+2(6y-2)

determiningTheFunctionDomain
2(6y-2)+8

We multiply parentheses

12y-4+8

We add all the numbers together, and all the variables

12y+4

Back to the equation:

-(12y+4)



We add all the numbers together, and all the variables

-4y-(12y+4)+6=0

We get rid of parentheses

-4y-12y-4+6=0

We add all the numbers together, and all the variables

-16y+2=0

We move all terms containing y to the left, all other terms to the right

-16y=-2

y=-2/-16

y=1/8

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