-2(3y-3)+3y=8+4(3y-5)

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Solution for -2(3y-3)+3y=8+4(3y-5) equation: 



-2(3y-3)+3y=8+4(3y-5)

We move all terms to the left:

-2(3y-3)+3y-(8+4(3y-5))=0

We add all the numbers together, and all the variables

3y-2(3y-3)-(8+4(3y-5))=0

We multiply parentheses

3y-6y-(8+4(3y-5))+6=0



We calculate terms in parentheses: -(8+4(3y-5)), so:

8+4(3y-5)

determiningTheFunctionDomain
4(3y-5)+8

We multiply parentheses

12y-20+8

We add all the numbers together, and all the variables

12y-12

Back to the equation:

-(12y-12)



We add all the numbers together, and all the variables

-3y-(12y-12)+6=0

We get rid of parentheses

-3y-12y+12+6=0

We add all the numbers together, and all the variables

-15y+18=0

We move all terms containing y to the left, all other terms to the right

-15y=-18

y=-18/-15

y=1+1/5

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