-2(3y-3)+8y=-2(y+2)

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Solution for -2(3y-3)+8y=-2(y+2) equation: 



-2(3y-3)+8y=-2(y+2)

We move all terms to the left:

-2(3y-3)+8y-(-2(y+2))=0

We add all the numbers together, and all the variables

8y-2(3y-3)-(-2(y+2))=0

We multiply parentheses

8y-6y-(-2(y+2))+6=0



We calculate terms in parentheses: -(-2(y+2)), so:

-2(y+2)

We multiply parentheses

-2y-4

Back to the equation:

-(-2y-4)



We add all the numbers together, and all the variables

2y-(-2y-4)+6=0

We get rid of parentheses

2y+2y+4+6=0

We add all the numbers together, and all the variables

4y+10=0

We move all terms containing y to the left, all other terms to the right

4y=-10

y=-10/4

y=-2+1/2

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