-2(3y-3)+8y=-4(y+2)

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Solution for -2(3y-3)+8y=-4(y+2) equation: 



-2(3y-3)+8y=-4(y+2)

We move all terms to the left:

-2(3y-3)+8y-(-4(y+2))=0

We add all the numbers together, and all the variables

8y-2(3y-3)-(-4(y+2))=0

We multiply parentheses

8y-6y-(-4(y+2))+6=0



We calculate terms in parentheses: -(-4(y+2)), so:

-4(y+2)

We multiply parentheses

-4y-8

Back to the equation:

-(-4y-8)



We add all the numbers together, and all the variables

2y-(-4y-8)+6=0

We get rid of parentheses

2y+4y+8+6=0

We add all the numbers together, and all the variables

6y+14=0

We move all terms containing y to the left, all other terms to the right

6y=-14

y=-14/6

y=-2+1/3

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