-2(3y-3)+9y=7+2(6y-8)

Solution for -2(3y-3)+9y=7+2(6y-8) equation:

-2(3y-3)+9y=7+2(6y-8)

We move all terms to the left:

-2(3y-3)+9y-(7+2(6y-8))=0

We add all the numbers together, and all the variables

9y-2(3y-3)-(7+2(6y-8))=0

We multiply parentheses

9y-6y-(7+2(6y-8))+6=0


We calculate terms in parentheses: -(7+2(6y-8)), so:

7+2(6y-8)

determiningTheFunctionDomain
2(6y-8)+7

We multiply parentheses

12y-16+7

We add all the numbers together, and all the variables

12y-9

Back to the equation:

-(12y-9)


We add all the numbers together, and all the variables

3y-(12y-9)+6=0

We get rid of parentheses

3y-12y+9+6=0

We add all the numbers together, and all the variables

-9y+15=0

We move all terms containing y to the left, all other terms to the right

-9y=-15

y=-15/-9

y=1+2/3