-2(3y-3)-y=-4(y-2)

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Solution for -2(3y-3)-y=-4(y-2) equation: 



-2(3y-3)-y=-4(y-2)

We move all terms to the left:

-2(3y-3)-y-(-4(y-2))=0

We add all the numbers together, and all the variables

-1y-2(3y-3)-(-4(y-2))=0

We multiply parentheses

-1y-6y-(-4(y-2))+6=0



We calculate terms in parentheses: -(-4(y-2)), so:

-4(y-2)

We multiply parentheses

-4y+8

Back to the equation:

-(-4y+8)



We add all the numbers together, and all the variables

-7y-(-4y+8)+6=0

We get rid of parentheses

-7y+4y-8+6=0

We add all the numbers together, and all the variables

-3y-2=0

We move all terms containing y to the left, all other terms to the right

-3y=2

y=2/-3

y=-2/3

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