-2(3y-4)-y=4(y-3)

Solution for -2(3y-4)-y=4(y-3) equation:

-2(3y-4)-y=4(y-3)

We move all terms to the left:

-2(3y-4)-y-(4(y-3))=0

We add all the numbers together, and all the variables

-1y-2(3y-4)-(4(y-3))=0

We multiply parentheses

-1y-6y-(4(y-3))+8=0


We calculate terms in parentheses: -(4(y-3)), so:

4(y-3)

We multiply parentheses

4y-12

Back to the equation:

-(4y-12)


We add all the numbers together, and all the variables

-7y-(4y-12)+8=0

We get rid of parentheses

-7y-4y+12+8=0

We add all the numbers together, and all the variables

-11y+20=0

We move all terms containing y to the left, all other terms to the right

-11y=-20

y=-20/-11

y=1+9/11