-2(3y-5)+6y=4(y+5)

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Solution for -2(3y-5)+6y=4(y+5) equation: 



-2(3y-5)+6y=4(y+5)

We move all terms to the left:

-2(3y-5)+6y-(4(y+5))=0

We add all the numbers together, and all the variables

6y-2(3y-5)-(4(y+5))=0

We multiply parentheses

6y-6y-(4(y+5))+10=0



We calculate terms in parentheses: -(4(y+5)), so:

4(y+5)

We multiply parentheses

4y+20

Back to the equation:

-(4y+20)



We add all the numbers together, and all the variables

-(4y+20)+10=0

We get rid of parentheses

-4y-20+10=0

We add all the numbers together, and all the variables

-4y-10=0

We move all terms containing y to the left, all other terms to the right

-4y=10

y=10/-4

y=-2+1/2

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