-2(3y-6)-5y=-5(-y+7)-10

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Solution for -2(3y-6)-5y=-5(-y+7)-10 equation: 



-2(3y-6)-5y=-5(-y+7)-10

We move all terms to the left:

-2(3y-6)-5y-(-5(-y+7)-10)=0

We add all the numbers together, and all the variables

-2(3y-6)-5y-(-5(-1y+7)-10)=0

We add all the numbers together, and all the variables

-5y-2(3y-6)-(-5(-1y+7)-10)=0

We multiply parentheses

-5y-6y-(-5(-1y+7)-10)+12=0



We calculate terms in parentheses: -(-5(-1y+7)-10), so:

-5(-1y+7)-10

We multiply parentheses

5y-35-10

We add all the numbers together, and all the variables

5y-45

Back to the equation:

-(5y-45)



We add all the numbers together, and all the variables

-11y-(5y-45)+12=0

We get rid of parentheses

-11y-5y+45+12=0

We add all the numbers together, and all the variables

-16y+57=0

We move all terms containing y to the left, all other terms to the right

-16y=-57

y=-57/-16

y=3+9/16

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