-2(3y-6)-y=-4(y-4)

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Solution for -2(3y-6)-y=-4(y-4) equation: 



-2(3y-6)-y=-4(y-4)

We move all terms to the left:

-2(3y-6)-y-(-4(y-4))=0

We add all the numbers together, and all the variables

-1y-2(3y-6)-(-4(y-4))=0

We multiply parentheses

-1y-6y-(-4(y-4))+12=0



We calculate terms in parentheses: -(-4(y-4)), so:

-4(y-4)

We multiply parentheses

-4y+16

Back to the equation:

-(-4y+16)



We add all the numbers together, and all the variables

-7y-(-4y+16)+12=0

We get rid of parentheses

-7y+4y-16+12=0

We add all the numbers together, and all the variables

-3y-4=0

We move all terms containing y to the left, all other terms to the right

-3y=4

y=4/-3

y=-1+1/3

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